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1. Why do we need to set the gradients manually to zero in pytorch?
2. pytorch loss.backward() calculates the gradient and cumsum it
3. How to learn best practices when you have no one to teach you?

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1. How to Develop a Word Embedding Model for Predicting Movie Review Sentiment: introduce how to do word embedding in keras and gensim and compare their performance on the movie review data.
2. Ludwig: a toolbox from uber that allows you to train and test deep learning models without ...

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1. Visualizing gradient descent in action An ineresting project to show how learning rate will affect the converge. If LR is too small, it will converge very slowly. If LR is too big(like 1.01), it will diverge.
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1. On AWS to connect with ServerAliveInterval=100

ssh -i ~/.ssh/xxxx.pem ubuntu@hithere.amazonaws.com -o ServerAliveInterval=100

2. General Setup

Many NAT firewalls time out idle sessions after a certain period of time to keep their trunks clean. Sometimes the interval between session drops is 24 hours ...

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1. Handling Categorical Data in Python
   • Categorical features may have a very large number of levels, known as high cardinality, (for example, cities or URLs), where most of the levels appear in a relatively small number of instances.
   • Many machine learning models, such as regression or SVM or ...

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1. What Kagglers are using for Text Classification
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4. Sutton & Barto Book: Reinforcement Learning: An Introduction
5. GitHub - sdmg15/Best-websites-a-programmer-should-visit: Some useful websites for programmers.
6. memory ram usage in linux bash echo "USER RSS PROCS" ; echo "-------------------- -------- -----" ; ps hax -o ...

summary of how to install nvidia drivers on ubuntu for deep learning.

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1. 如何配置一台适用于深度学习的工作站？
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7. Build TensorFlow-GPU with CUDA 9.1 MKL and Anaconda Python 3.6 using a Docker Container
8. 到底什么是生成式对抗网络GAN？

# Dockerfile to ...

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1. AWS Activating TensorFlow
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题目大意 给定n个气球，每个气球有一个数字，用数组nums来表示n个气球上面的数字。如果气球i被打破，那么你会得到nums[left] * nums[i] * nums[right].这里left和right分别为气球i的左右两边的气球。打破所有的气球后把所有的数字相加，求解怎么打破这些气球使得最后得到的数字最大。